Fix time() on 1.8.7

The time() function takes an argument of a timezone, and always returns
time in epoch format. The epoch format is the number of seconds that
have elapsed since January 1, 1970 (midnight UTC/GMT), not counting leap
seconds. This means that it is universally the same regardless of
timezones.

I don't know what the timezone argument is supposed to do, and it is not
documented. So lets just make 1.8.7 work like > 1.8.7

1 files changed, 2 insertions, 9 deletions

diff --git a/spec/functions/time_spec.rb b/spec/functions/time_spec.rb
index 2875e25..d157939 100755
--- a/spec/functions/time_spec.rb
+++ b/spec/functions/time_spec.rb
@@ -7,7 +7,7 @@ describe 'time' do
   context 'when running at a specific time' do
     before(:each) {
       # get a value before stubbing the function
-      test_time = Time.utc(2006, 10, 13, 8, 15, 11, '+01:00')
+      test_time = Time.utc(2006, 10, 13, 8, 15, 11)
       Time.expects(:new).with().returns(test_time).once
     }
     it { is_expected.to run.with_params().and_return(1160727311) }
@@ -16,13 +16,6 @@ describe 'time' do
     it { is_expected.to run.with_params({}).and_return(1160727311) }
     it { is_expected.to run.with_params('foo').and_return(1160727311) }
     it { is_expected.to run.with_params('UTC').and_return(1160727311) }
-
-    context 'when running on modern rubies', :unless => RUBY_VERSION == '1.8.7' do
-      it { is_expected.to run.with_params('America/Los_Angeles').and_return(1160727311) }
-    end
-
-    context 'when running on ruby 1.8.7, which garbles the TZ', :if => RUBY_VERSION == '1.8.7' do
-      it { is_expected.to run.with_params('America/Los_Angeles').and_return(1160702111) }
-    end
+    it { is_expected.to run.with_params('America/New_York').and_return(1160727311) }
   end
 end