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#
# Copyright (c) 2014 ThoughtWorks, Inc.
#
# Pixelated is free software: you can redistribute it and/or modify
# it under the terms of the GNU Affero General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
#
# Pixelated is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Affero General Public License for more details.
#
# You should have received a copy of the GNU Affero General Public License
# along with Pixelated. If not, see <http://www.gnu.org/licenses/>.
from email.utils import parseaddr
from pixelated.support.functional import flatten
from whoosh.qparser import QueryParser
from whoosh import sorting
from whoosh.query import Term
def address_duplication_filter(contacts):
contacts_by_mail = dict()
for contact in contacts:
mail_address = extract_mail_address(contact)
current = contacts_by_mail.get(mail_address, '')
current = contact if len(contact) > len(current) else current
contacts_by_mail[mail_address] = current
return contacts_by_mail.values()
def bounced_addresses_filter(searcher, contacts):
query = QueryParser('bounced', searcher.schema).parse('*')
bounced_addresses = searcher.search(query,
limit=None,
groupedby=sorting.FieldFacet('bounced',
allow_overlap=True)).groups()
return set(contacts) - set(flatten([bounced_addresses]))
def extract_mail_address(text):
return parseaddr(text)[1]
def contacts_suggestions(query, searcher):
return address_duplication_filter(bounced_addresses_filter(searcher, search_addresses(searcher, query))) if query else []
def search_addresses(searcher, query):
restrict_q = Term("tag", "drafts") | Term("tag", "trash")
results = []
for field in ['to', 'cc', 'bcc', 'sender']:
query_parser = QueryParser(field, searcher.schema)
results.append(searcher.search(query_parser.parse("*%s*" % query),
limit=None,
mask=restrict_q,
groupedby=sorting.FieldFacet(field,
allow_overlap=True)).groups())
return flatten(results)
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