blob: 650c15dc56ff8e573316b90342a6f820501f8ffc (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
|
module BillingHelper
def braintree_form_for(object, options = {}, &block)
options.reverse_merge! params: @result && @result.params[object],
errors: @result && @result.errors.for(object),
builder: BraintreeFormHelper::BraintreeFormBuilder,
url: Braintree::TransparentRedirect.url
form_for object, options, &block
end
def billing_top_link(user)
# for admins, top link will show special admin information, which has link to show their own customer information
if (admin? and user == current_user)
billing_admin_path
else
:index_subscription
end
end
def show_or_new_customer_link(user)
# Link to show if user is admin viewing another user, or user is already a customer.
# Otherwise link to create a new customer.
if (admin? and (user != current_user)) or ((customer = Customer.find_by_user_id(user.id)) and customer.has_payment_info?)
show_customer_path(user)
else
new_customer_path
end
end
# a bit strange to put here, but we don't have a subscription model
def user_for_subscription(subscription)
if (transaction = subscription.transactions.first)
# much quicker, but will only work if there is already a transaction associated with subscription (should generally be)
braintree_customer_id = transaction.customer_details.id
else
credit_card = Braintree::CreditCard.find(subscription.payment_method_token)
braintree_customer_id = credit_card.customer_id
end
customer = Customer.find_by_braintree_customer_id(braintree_customer_id)
user = User.find(customer.user_id)
end
def allow_cancel_subscription(subscription)
['Active', 'Pending'].include? subscription.status or (admin? and subscription.status == 'Past Due')
end
end
|
